Problem
Merge two sorted (ascending) linked lists and return it as a new sorted list. The new sorted list should be made by splicing together the nodes of the two lists and sorted in ascending order.
Example
Given 1->3->8->11->15->null, 2->null
, return 1->2->3->8->11->15->null.
Note
先考虑l1和l2有无空集,有则返回另一个。
新建链表dummy,指针node将l1和l2较小的放在链表顶端,然后向后遍历,直到l1或l2之一为空。再将非空的链表放在node后面。最后返回dummy.next结束。Solution
public class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if (l1 == null) return l2; if (l2 == null) return l1; ListNode dummy = new ListNode(0), node = dummy; while (l1 != null && l2 != null) { if (l1.val < l2.val) { node.next = l1; l1 = l1.next; } else { node.next = l2; l2 = l2.next; } node = node.next; } if (l1 != null) node.next = l1; if (l2 != null) node.next = l2; return dummy.next; }}